Let p(x) be a polynomial with real coefficients such that p(n)=p(n-1) for any positive integer n. Prove that p(x)=p(0) for all x∈R.
This looks like a proof by induction. Start with n=1. You know that \(p(1)=p(1-1)=p(0)\). Assume it's true up to some integer \(k\), and show that it's true for \(k+1\).
but x may not be a integer.
Good point. Induction only takes care of the positive integers.
Is this the entire problem? If so, you could create a counterexample using the taylor expansion for \(\sin(x)\) such that it has a period of 1.
They might mean a finite polynomial. Weird things start happening when you consider infinite polynomials like taylor series.
very true. If it's finite, then this proposition is true.
thank you very much!
Did we do anything o.O lol
Not that I know of... does @Davidc still want help on proving this for finite degree polynomials?
no
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