I want to learn about Sigma Notation. I know that it's used for finding the sum of a sequence. How do you write it?
\[\text{\sum}\longrightarrow \sum\]
No, not latex.. I mean, how exactly is it written?
What is the number above the term and below?
\[\large \sum_{n=1}^n n = 1+ 2+3+4+\ldots+n\]
What is meant by this?
It's sum of first \(n\) natural numbers.
Rather, representation of sum of first \(n\) natural numbers.
I did understand. But why is n equal to 1 + 2 + 3 + 4...n
Shouldn't it be: \(\Large \color{purple}{\rightarrow \sum_{n = 1}^{n}(1 + 2 + 3 + 4....n) }\)
Hmm \[\large 1 + \sum_{n=2}^n n= 1 + 2+\ldots +n\implies 1 + 2+3+\sum_{n=4}^n=1+2+\ldots +n \] Do you get it now?
Sorry.
It's supposed to be \[1+2+3+\sum_{n=4}^nn=1+2+\ldots+n\]
Oops, that's even more confusing @Ishaan94
If it were for your representation then it would be, \[\large\sum_{n=1}^n\left(1+2+3+\ldots+n\right) = 1 +\left(1+2\right)+\left(1+2+3\right)+\ldots +\left(1+2+\ldots +n\right)\]
I mean what do you mean by the n = 4 in the bottom, and n on the top?
argh, bad latex :/
lol :D
Hmm the \(n\) is evaluate from 4 to \(n\). 4 is the initial value and \(n\) is the final value.
I am a bad teacher :/
Oh, I'm getting it.
So, it's the sum of values when you substitute n with 4, then 5, then 6, then 7 till n.
Let f(n) be any function or expression.\[\sum_{n=1}^nf(n)\]Then,\[\sum_{n=1}^n f(n)=f(1) + f(2)+\ldots +f(n)\]
Don't say that. I'm a bad learner.
I am getting it... wow, that makes sense!
"So, it's the sum of values when you substitute n with 4, then 5, then 6, then 7 till n." Yes. Exactly.
it's been discussed to me countless times i still dont get it =_= i never boother nowadays
So, wait, let me try to get the sum of first n natural numbers.
learn about mathematical induction @ParthKohli it's fun :P
For example, \[\sum_{n=1}^nn^2 =1 + 2^2 + 3^2 + \ldots + n^2 \]
Yes, you should learn Mathematical Induction. It's fun. and at times challenging.
|dw:1337152400065:dw| Is this the sum of first 4 natural numbers?
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