A motorcycle stunts man belonging to a fair, rides over the vertical walls of a circular well at an average speed of 54 kph for 5 minutes. If the radius of the well is 5 meters then the distance traveled is
@ParthKohli please help
@lgbasallote please help
will it depend on the radius of the well?
sounds like circular motion....
54 kph = 54000meters per hour 54000/5 = 10,800 meters.
10.8 kilometers.
lol that's a big well :p
4.5 km
no wrong ans. is 4.5 kms.
Oh lol
get the circumference first 54 x 1/12 hours = 4.5
just find out the distance covered in 5 minutes. 54 km in 60 minutes so, in 1 minute, 54/60 km in 5 minutes, 54/60 * 5 km=4.5 km
I meant ur ans is wrong ... correct ans is 4.5 kms
but does the raidus even matter =))
Maybe the mods will punish me.. I should answer questions I know
i guess not, @lgbasallote :)
i answer a lot of questions blindly parth :P just dont take the populated ones....
too many witnesesses @ParthKohli =_=
radius is given just for fun, i guess.. :/
thanks @Arnab09
you guys are fun
well you could add a part b) to the question: how many times did he ride around the well? divide distance by circumference: 4500/10pi = 1413.7
he went around a thousand times?? ill be dizzy if i were him
HEHEHE
:D
lol it should be 143 @dumbcow :P
My profession, certainly not in circus.
Oh this is great really very great
Then what do u think ... people who are replying work in circus.....@ParthKohli
@lgbasallote , you sure? 4.5km = 4,500m
Thanks Guys
4500/10 = 450...450/3.14 is 143.3
haha i Fail....forgot parenthesis on 10pi in calculator
:PPP
I'm thinking of using \[v=54kph\] \[v=15ms^{-1}\] maybe you could find the angular velocity \[v=r \omega\] \[\omega=3rad/s\] -------------------------------- Then use \[\theta=\omega t+\frac{1}{2}\alpha t^2\]
Since there's no angular acc, θ=ωt θ=(3)(300)=900radians
Which is 900m
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