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OpenStudy (anonymous):
evaluate the integral (5)/(sqrt(10x+2))dx
A. sqrt(x^2+x)+C
B. .5(sqrt(x^2+x)+C
C. 1/(sqrtx^2+x)+C
D. sqrt(2x+1)+C
E. none
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OpenStudy (turingtest):
u-substitution integral\[u=10x+2\implies du=10dx\]
OpenStudy (anonymous):
so it's E??
OpenStudy (turingtest):
I don't think so
what is your integral after making the u-substitution?
OpenStudy (anonymous):
put sqt<10x+2>as u......u will get it........
OpenStudy (turingtest):
actually I don't think I see the right answer on there...
are you sure there are no typos here?
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sam (.sam.):
i think its none
OpenStudy (turingtest):
Oh I'm sorry I read D for E
@quyenthuy820 was correct :p
OpenStudy (anonymous):
thank you guys!
sam (.sam.):
yeah it should be \[\sqrt{10 x+2}\]
OpenStudy (lgbasallote):
lol turing :p
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OpenStudy (anonymous):
yes none of these answer is in [log{sqt<10x+2>}]/2
OpenStudy (turingtest):
well a little dyslexia makes math more fun anyway ;)
OpenStudy (anonymous):
evaluate (cos3x)/(sin3x)dx ??
i got: 1/3log(sin(3x))
is that correct?
OpenStudy (turingtest):
yes :)
OpenStudy (turingtest):
+C
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OpenStudy (anonymous):
evaluate (e^x)/(2-e^x)dx
i got -log(2-e^x)+C ??
OpenStudy (turingtest):
yes it's also right, but...
could you please post each Q separately from now on? them's the rules.
thanks
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