Question

Solve for x to four significant digits....

Answer 1

You mean like this \[7^{2x-1}=316\]

Answer 2

^thats right

Answer 3

i calculator might be useful

Answer 4

7^{2x-1}=316
ln(7^{2x-1})=ln(316)
(2x-1)ln(7)=ln(316)
(2x-1)=ln(316)/ln(7)
\[x=\frac{\ln(316)}{2\ln(7)}+1\]

Answer 5

^all I have is the computer one

Answer 6

so x=????

Answer 7

you can download microsoft mathematics for a better calculator, its free
http://www.microsoft.com/en-us/download/details.aspx?id=15702

Answer 8

7^(2x−1) = 316

7^(2x) = 7*316

2x = log7(7*316)

x = (1+log7(319))/2

Answer 9

Thanks everyone

Answer 10

Sam typoed the last term :)

Answer 11

and i typoed the 316 in the end

Answer 12

lol

Answer 13

so x = 1.979

Answer 14

Should be\[x=\frac{\ln(316)}{2\ln(7)}+\frac{1}{2}\]

Answer 15

@adjaharrison Thanks

Answer 16

@adjaharrison yes