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Mathematics 8 Online
OpenStudy (anonymous):

Simplify completely: 2x^2 + 20x + 32 / x^2 - 2x - 80

OpenStudy (anonymous):

[ 2x^2 + 20x + 32 ] / [ x^2 - 2x - 80 ] [ 2 ( x^2 + 10x + 16) ] / [ x^2 - 2x - 80 ] simplify both denominator & numerator : [ 2 (x+2) (x+8) ] / [ (x+8) (x-10) ] crossing out the common (x+8), we get : [ 2(x+2) ] / [ (x-10) ] You can verify the final result by plugging in the same value of 'x' for both initial and final equation. If both yield the same answer, then it's correct.

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