Question

r^2 + 4.3r-0.9=0

Answer 1

NEED HELP

Answer 2

solve?

Answer 3

Indeed

Answer 4

\[\begin{array}{l} \text{Add }0.9\text{ \to both sides:} \\ r^2+4.3 r=0.9 \\ \text{Add }4.6225\text{ \to both sides:} \\ r^2+4.3 r+4.6225=5.5225 \\ \text{Factor the \left hand side:} \\ (r+2.15)^2=5.5225 \\ \text{Take the \square \root of both sides:} \\ |r+2.15|=2.35 \\ \text{Eliminate the absolute value:} \\ r+2.15=-2.35\text{ or }r+2.15=2.35 \\ \text{Subtract }2.15\text{ from both sides:} \\ r=-4.5\text{ or }r+2.15=2.35 \\ \text{Subtract }2.15\text{ from both sides:} \\ r=-4.5\text{ or }r=0.2 \\\end{array}\]

Answer 5

thank u so much :)

Answer 6

I would have used the quadratic formula but thats your call...

Answer 7

how can i use the quadratic formula for it?

Answer 8

\[(-b \pm \sqrt{b^2}-4ac)/2a, where a, b, and c are the numbers before r^2, r^1, and r^0.\]