Ask your own question, for FREE!
Mathematics 9 Online
OpenStudy (zepp):

What?? D: Can somebody explain why this is possible?

OpenStudy (zepp):

OpenStudy (kinggeorge):

The proof involves dividing by 0. Namely, \(x-x=0\)

OpenStudy (zepp):

Oh, I see, thanks :)

OpenStudy (kinggeorge):

You're welcome.

OpenStudy (dumbcow):

yes they are a lot of these 1=2 "proofs" out there and they involve dividing by 0 in some way the premise was 0=0 to begin with

OpenStudy (zepp):

Aight, because that looks credible at the first glance :[

OpenStudy (kinggeorge):

Here's a personal favorite\[\large e={e^{2 \pi i \over 2\pi i}}=(e^{2\pi i})^{1 \over 2\pi i}=1^{1 \over 2\pi i}=1\]

OpenStudy (dumbcow):

haven't seen that one...little harder to spot the flaw

OpenStudy (zepp):

Can't see it o.O

OpenStudy (dumbcow):

i believe this is why http://en.wikipedia.org/wiki/De_Moivre%27s_formula#Failure_for_non-integer_powers since power here is 1/i2pi theorem does not hold i could be wrong i guess

OpenStudy (kinggeorge):

To the best of my knowledge, \[\large 1^{1 \over 2\pi i}=1\]The error occurs elsewhere.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!