What?? D: Can somebody explain why this is possible?
The proof involves dividing by 0. Namely, \(x-x=0\)
Oh, I see, thanks :)
You're welcome.
yes they are a lot of these 1=2 "proofs" out there and they involve dividing by 0 in some way the premise was 0=0 to begin with
Aight, because that looks credible at the first glance :[
Here's a personal favorite\[\large e={e^{2 \pi i \over 2\pi i}}=(e^{2\pi i})^{1 \over 2\pi i}=1^{1 \over 2\pi i}=1\]
haven't seen that one...little harder to spot the flaw
Can't see it o.O
i believe this is why http://en.wikipedia.org/wiki/De_Moivre%27s_formula#Failure_for_non-integer_powers since power here is 1/i2pi theorem does not hold i could be wrong i guess
To the best of my knowledge, \[\large 1^{1 \over 2\pi i}=1\]The error occurs elsewhere.
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