Question

cube root of ((a^6)(b^9))/-64

Answer 1

\[\Large \sqrt[3]{a^6b^9 \over -64}={\sqrt[3]{a^6b^9} \over \sqrt[3]{-64}}\]Can you tell me what the cube root of \(a^6b^9\) is?

Answer 2

dont you do \[(a ^{6}b ^{9})^{1/3}\]

Answer 3

It's the same exact thing, just a slightly different way of writing it. Can you solve that yourself?

Answer 4

no i'm not sure how to. what do you do with the exponents in the numerator?

Answer 5

In this case, you can do the following. \[\Large (a^6b^9)^{1/3}=a^{6/3}\cdot b^{9/3}=a^2b^3\]You can actually distribute the exponent to the terms inside the parentheses.

Answer 6

So that would be the numerator. Could you tell me what \((-64)^{1/3}\) is?

Answer 7

-4. thanks

Answer 8

Exactly. You're welcome.