a^2+b^2=10^2

What will work for this, what would a and b be?

Question

a^2+b^2=10^2 

What will work for this, what would a and b be?

blockcolder · Answer

5sqrt(2) for a and b would work.

anonymous · Answer

but that would be 50 instead of 100

blockcolder · Answer

$$(5\sqrt{2})^2=50\
50+50=100$$

paxpolaris · Answer

the only integral solutions ... i think are: 
a=6, b=8

a=8, b=6

anonymous · Answer

I was looking for a simpler answer but thank you

anonymous · Answer

directed o blockcolder

anonymous · Answer

*to

directrix · Answer

@smoothiebit123
 I'm thinking there may be infinitely many points that work, all located on a circle of radius 10.

directrix · Answer

Center of circle would be (0,0).
Question: Do you want only integer values of a and b?

anonymous · Answer

i was doing Pythagorean therom

directrix · Answer

Regardless, there are infinitely many solutions that are positive a and the corresponding positve b which lie on the quarter circle in quadrant one of the circle. The Pythagorean Theorem, the formula for a circle, and the distance formula are inextricably related.

Bottom Line: There is no unique a and b which are solutions to the equation you posted.