Question

what is the simplified form of... (5/3y-2)-(4/9y^2-4)

Answer 1

\[\frac{5}{3y-2}-\frac{4}{9y^2-4}\] like that?

Answer 2

yep

Answer 3

k then we need a common denominator in order to subtract, as with ordinary fractions
\[9y^2-4=(3y+2)(3y-2)\] so your common denominator is
\[(3y+2)(3y-2)\] subtract as follows
\[\frac{5}{3y-2}-\frac{4}{9y^2-4}=\frac{5(3y+2)-4}{(3y+2)(3y-2)}\]then some algebra to clean up the numerator

Answer 4

you got that part ?

Answer 5

yah its ether 15y+x/(3y-2)(3y+2) or the bottom are both plus 2

Answer 6

hold the phone. there is no \(x\) here

Answer 7

should be
\[\frac{15y+6}{(3y+2)(3y-2)}\]