What is the remainder of
(x3 – 6x – 9x + 3) ÷ (x - 3)
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sam (.sam.):
Long division
sam (.sam.):
or f(3)=(x3 – 6x – 9x + 3)
OpenStudy (anonymous):
you have a choice
you can either divide by \(x-3\) and see what you get, or you can replace \(x\) by 3
that will also give you the remainder.
what .sam. said
sam (.sam.):
there's a missing x^2
OpenStudy (anonymous):
no x^3 is what it is suppose to say
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sam (.sam.):
f(3)=x^3 – 6x^2 – 9x + 3??
OpenStudy (anonymous):
yes
sam (.sam.):
the 6x is it 6x^2?
OpenStudy (anonymous):
no
sam (.sam.):
then you add the like terms first
f(3)=(x3 – 6x – 9x + 3)
f(3)=(x3 –15x + 3)
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OpenStudy (anonymous):
(x^3 – 6x – 9x + 3) ÷ (x - 3) is how it reads and the calculator gave me a strange answer
sam (.sam.):
Substitute 3 into x,
f(3)=((3)^3 –15(3) + 3)
f(3)=-15
sam (.sam.):
reamainder is -15
OpenStudy (callisto):
Wouldn't it be better to write f(x)=(x^3 –15x + 3)?
when it's f(3) =... I think you should sub. x by 3...
OpenStudy (anonymous):
that isnt an answer option
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sam (.sam.):
I think its f(x)=(x3 – 6x^2 – 9x + 3)
sam (.sam.):
f(3)=(x3 – 6x^2 – 9x + 3)
remainder=-51
sam (.sam.):
is it?
OpenStudy (anonymous):
A. -51
B.-51/x - 3
C. -17/x
D. -17/ x - 3
sam (.sam.):
-51
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