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A certain polynomial p(x) of degree greater than 2 when divided by (x+2) and (x-1) leaves reminders -9 and 9 respectively. the remainder when p(x) is divided by (x+2)(x-1) is?
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@FoolForMath plz help
option are 6x^2 +3 3 6x +3 3x + 6
See if this helps, \[P(-2)=-9\] \[P(1)=9\]
FoolFm is right
ok then wat to do next?
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6x +3
yes the answer is 6x+3 can u tell the steps
the remainder should have the same value as p in 1 and -2
then how it came 6x+3
p=(x-1)(x+2)Q+R
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ok next??
so p(1)=R(1) and p(-2)=R(-2)
ok....
|dw:1337252793389:dw|
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