Question

how to do quadratic equations???

Answer 1

By solving them.

Answer 2

Just kidding, what do you want to solve?

Answer 3

this always works
\[x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}\]

Answer 4

basically, a quadratic equation is in the form of:


\(\Large \color{MidnightBlue}{\Rightarrow ax^2 + bx + c = 0 }\)

Answer 5

@NotSObright make it simple, silly :)

Answer 6

Other methods
-Factorization
-Completing Squares

Answer 7

First, you have to factor by grouping.

Answer 8

Factoring is a very easy method.

Answer 9

example: n^2 = -4n + 21

Answer 10

@ParthKohli I don't really get nerd jokes so knock it off

Answer 11

Okay, @mathismyworstsubject

First, get it in the general form like I posted.

Answer 12

Bring all the things in one side and 0 on the other.

Answer 13

\[x=-b \pm \sqrt{b*b-4ac}diva2\] is the general eqn

Answer 14

Use factorization
split middle term so that the nos when multiply to give the constant term
4 as 7 -3 because 7*-3=-21

Answer 15

this is too hard. im doing the x box method. bye!

Answer 16

\(\Large \color{MidnightBlue}{\Rightarrow n^2 + 4n - 21 = 0 }\)

\(\Large \color{MidnightBlue}{\Rightarrow n^2 + 7n - 3n - 21 = 0 }\)

\(\Large \color{MidnightBlue}{\Rightarrow n(n + 7) - 3(n + 7) = 0 }\)

\(\Large \color{MidnightBlue}{\Rightarrow (n - 3)(n + 7) = 0 }\)

We know that a number multiplied by another number is 0.

So, either n - 3 = 0 or n + 7 = 0

n = = 0 + 3 = 3
OR
n = 0 - 7
n = -7

Answer 17

I'd prefer the quadratic equation anytime over factoring! It's super fast and easy:)