Find the intersection points of:
x = sin(y)
y^2 - pi^2 = x

Hint please

Question

Find the intersection points of:
x = sin(y)
y^2 - pi^2 = x

Hint please

anonymous · Answer

substitute equation 1 to equation 2
I think

anonymous · Answer

i would start with 
$$y^2-\pi=\sin(y)$$

anonymous · Answer

after that i would be stuck

turingtest · Answer

lol

anonymous · Answer

I just know the answer

anonymous · Answer

@satellite73  by the way he only ask for the hint 
xD

anonymous · Answer

http://www.wolframalpha.com/input/?i=x^2-pi+%3D+sin%28x%29

anonymous · Answer

Suppose I cannot use graphing calculator.

turingtest · Answer

I don't think any of us has given a good hint so far, because I don't think any of us knows how to solve it yet
I would maybe start thinking about$$y=\sqrt{x+\pi^2}$$

anonymous · Answer

then i have no idea unless you want so start with 
$$\sin(x)-x^2+\pi=0$$ and use newton ralphson

anonymous · Answer

y = arcsin(x), and y = \sqrt{pi^2 - x}?

anonymous · Answer

y^2 - pi^2 = sin(y)...
y=pi
:)

anonymous · Answer

OH!

anonymous · Answer

oooooooooooooooh it is $\pi^2$ not $\pi$!!

turingtest · Answer

but that won't help
that is clearly an answer by inspection.... if that counts
I thought you wanted a method

turingtest · Answer

the "but that won't help" part was in reference to an earlier comment

anonymous · Answer

Yeah by inspection it would work. But the full question asks to find the area A of the region enclosed by the functions y = sin(y) and y^2 - pi^2 = x

anonymous · Answer

sorry, x = sin(y), not y = sin(y)

anonymous · Answer

then inspection is what you need !

turingtest · Answer

I guess :(

anonymous · Answer

Oh, then pi and -ve pi are the answers?

anonymous · Answer

I just realized that -pi would also give LHS = RHS

turingtest · Answer

yes

anonymous · Answer

Wait, so then the bounded region is -ve pi to pi, and the right function is sin(y) and the left function is y^2 - pi^2 = x

turingtest · Answer

yeah

anonymous · Answer

here is the picture, correct this time http://www.wolframalpha.com/input/?i=x^2-pi^2+%3D+sin%28x%29

anonymous · Answer

(i think, track record not so good this morning)

anonymous · Answer

Ok from there on, I got it. Thanks for your help. I do not know who to give medal too though.. :/

anonymous · Answer

not me!

turingtest · Answer

your link did not work for me sat http://www.wolframalpha.com/input/?i=plot%20x%3Dsiny%2C%20y%5E2-pi%5E2%3Dx&t=crmtb01