Ask your own question, for FREE!
Physics 16 Online
OpenStudy (anonymous):

A 1200 kg car moving north at 50 km/h collides with a 1600-kg car moving east at 30 km/h. The cars stick together, and the wreckage moves off at an initial speed of a. 27 km/h b. 38 km/h c. 39 km/h d. 58 km/h *follow up question • The direction in which the wreckage of he preceding collision moves off is a. 39° E of N b. 45° E of N c. 51° E of N d. 54° E of N

OpenStudy (anonymous):

@asya here it is given that the cars stick to each other after the collision. So, this is a n inelastic collision. In an inelastic collision, can you tell me quantities that are conserved?

OpenStudy (anonymous):

total energy and momentum.

OpenStudy (anonymous):

only momentum in case of inelastic collision.

OpenStudy (anonymous):

apply the conservation of momentum you will get the ans. of first part.

OpenStudy (anonymous):

total energy will remain always conserved for any isolated sysetm. For Elastic collision conserved quantities are: 1. Kinetic energy 2. Momentum 3. Total energy For Inelastic collision conserved quantities are: 1. Momentum 2. Total energy.

OpenStudy (anonymous):

okay. in that frame of reference yes. total energy.

OpenStudy (anonymous):

i mean context

OpenStudy (anonymous):

For Determining direction: You know P1(momentum of 1st particle), P2(momentum of 2nd particle) and P (final momentum) then apply the triangle/parallelogram law of vector addition

OpenStudy (anonymous):

@chand Even in this context both quantities are conserved but we don't need total energy for our answer.

OpenStudy (anonymous):

right. when you were saying total energy, i thought you were referring to total mechanical energy(potential and kinetic). so i just got confused there.

OpenStudy (mos1635):

|dw:1337286145791:dw| |dw:1337286263195:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!