Question

Calculate the freezing point of a 2.6-molal aqueous sucrose solution. The freezing point depression constant for water is 1.86 degrees C/molal.
4.8 °C
1.4 °C
-1.4 °C
-4.8 °C

Answer 1

\[\delta T_f = K_f * m\]

Where delta T_f is change in freezing point

K_f-->freezing constant
m-->molality

Answer 2

\[Tf = 1.86 * 2.6\]So it would be?

Answer 3

yes

Answer 4

- 4,8 °C !!!