Question

can someone show me how to do this, i want to learn how.
logsub a (2^a) =a/4, a=...
a)2
b)4
c)8
d)16
e)32

Answer 1

\[\log_a(2^a)={a \over 4}\]\[a \cdot \log_a (2)={a \over 4}\]Cancel the \(a\)'s\[\log_a(2)={1 \over4}\]Therefore, \[a^{1 \over 4}=2\]By the definition of logs. This means that \[a=2^4=16\]

Answer 2

ok, thanks

Answer 3

You're welcome.