Ron is moving out of his apartment. To be more organized for the moving process, he stacked the boxes up in threes. Each box has dimensions of 22 inches by 22 inches by 22 inches. What is the surface area of the rectangular prism formed by the 3 stacked boxes?
14*22*22
I don't think the surface area would be the result of the surface area of one box times 3. I think you would calculate the height of the column of boxes. H= 22 + 22 + 22 or H=66 in. The length and width would remain at 22 in. X 22 in. The surface area would be the area of the four sides or 4(66 X 22) =5808 sq in. plus the area of the top and bottom which would be 2(22 X 22)=968 sq in. Total surface area would be 5808 + 968 = 6,776 sq in. or approx 47.05 sq ft.
thank you your aswesome
You're welcome, cinar also got the same answer.
oh!
Which of the following statement is true? Answer There is only one way to calculate the surface area of a composite figure. The interior faces of a composite figure should be added to its total surface area. The surface area of a composite figure is measured in cubic units. There is only one correct answer for the surface area of a composite figure.
He did it by counting the number of exposed 22 X 22 panels. That works also.
The last statement is a true statement.
There is only one correct answer for the surface area of a composite figure.
that one?
im done typing i dont know why it shows im still typing
Yes that seems to me to be the best one.
A canister with a lid is shown. The body's height is four times the height of the lid. If h represents the height of the can's body, which expression could be used to determine the surface area of this canister?
I read your profile, and I think you are an honest person.
Thank you sir.
Do you have a picture of the cannister?
A canister with a lid is shown. The body's height is four times the height of the lid. If h represents the height of the can's body, which expression could be used to determine the surface area of this canister?
Is the cannister a cylinder?
Or is it a cube?
thats what im trying to figure out
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