Not able to get it :| x^12 - x^9 + x^4 - x + 1 ---> Find DOMAIN.
Incorrectly typed. Its, The same expression in a sqrt.
@siddhantsharan Is there any value of x which will make \[x^{12}-x^9+x^4+1\ \text{undefined}??\]
Yep. When its negative.
So what x can't be or should be?
How do I figure out when is this expression negative?
Basically the condition imposed should be, x^12 - x^9 + x^4 - x + 1 > 0
Yeah you're right, l'm also thinking
@experimentX Help?
lol ... seems factorization .. huge factorizaton
Yeah. It can be written as x(x^8 +1)(x^3 - 1) + 1 > 0 Intuitively that does help as we can see that its valid for all R. But how do you prove it mathematically? Or how does the factorization help.
from here, x >= 1 or x<= -1
How?
x^8 is always +ve, so, x(x^3-1) must always be +ve
lol, x<0 also satisfies condition
No. Not necessarily. There is a + 1 too. That makes a lot of diff here.
i guess (0,1) must be excluded
You cant say that. If x < 0 Then it is always satisffied. And check for 1/2. Its still satisfying.
does not satisfy..
Does.
It gives 0.53 approximately.
No, graph x(x^3 - 1)(x^ 8 + 1) + 1. You cant ignore the rest of the terms as they matter a lot for x between 0 to 1.
http://www.wolframalpha.com/input/?i=x%28x%5E3+-+1%29%28x%5E+8+%2B+1%29++%2B+1
You get me right?
Oh ... sorry,
lol. :)
x(x^8+1)(x^3-1) > -1
Yep.
it implies, x(x^3 -1) > -1/(x^8+1) It seems it satisfies this property for all values of x
as x->0, x(x^3 -1)->0 > -1 as x<0, x(x^3 -1>0 > -1 for, x>1, x(x^3 -1)>0>-1 the only place we need to check is (0,1) the minimum value is http://www.wolframalpha.com/input/?i=minima+x%28x^3+-+1%29%28x^+8+%2B+1%29 > -1 So the domain is all real numbers
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