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6∕√3
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@jazy i really dont understand these !
You can't have a radical in the denominator so mutliply √3 by the numerator and denominator: 6√3 (keep this) ------ √3 * √3 = √9 The square root of 9 is 3 so: 6√3 ---- 3
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The 6√3 is the same as if I were saying 6*√3. We leave that part alone now. Then in the denominator, anything multiplied by itself is going to give a square and, in the end you'll end up with the orginal number but without a radical sign: √3 * √3 gave me √9 which is 3 so I ended up with a 3 and no radical:) Do you see what I mean?
so 6/√3 = 6√3 /3
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\[6/\sqrt{3}\times \sqrt{3}/\sqrt{3}\]
=\[6\sqrt{3}/3\] =\[2\sqrt{3}\]
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