Find the lateral and total area for the prism. Also find the volume
anyone?
lateral area = 3*18 +2(3*3(sqrt3)/2) =54 +9sqrt3 h=3*sin60 =3*(sqrt3)/2 volum=area of base *h/2
volum=(18*3sqrt3)/2 =27sqrt3
1. Lateral Area = Area of 3 Rectangular faces = 3 x (3 x 6) = 54 2. |dw:1337282500499:dw| h = √(3² - 1.5²) =2.59807 Area of Triangle : A = (0.5 x 2.5987 x 3) = 3.89805 Total Area = Lateral area + ( Area of Two Bases) = 54 + 2(3.89805) = 61.7961
need the answer in exact form
h = √(3² - 1.5²) =(3√3) / 2 Area of Triangle : A = 0.5 x [(3√3) / 2] x 3 = 9√3 / 4 Total Area = Lateral area + ( Area of Two Bases) = 54 + 2(9√3 / 4) = 54 + (9√3 / 2)
Volume = Area of one Triangle x depth =[ 9√3 / 4] x 6 = (27√3) / 2
for the total area I have a format like this:\[xx+ x/xSqrt X\]
got that
(9√3 / 2) is the same as (27/ 2√3) so, = 54 + (27/ 2√3)
Need the total area and volume of this prism too
Anyone?
Total Area = Area of Two right-angle Triangulars + Area of 3 rectangular faces Area of one right-angle Triangular = 0.5 x 6 x 4 = 12 |dw:1337284244591:dw| x= √(4² +6² ) = 2√13 If you unfold the prism, you can consider it as a single rectangle |dw:1337284395550:dw| Area of single Rectangle = 8 x (6+4+ 2√13) = 80 +16√13 Total Area = Area of Two right-angle Triangulars + Area of 3 rectangular faces Total Area = Area of Two right-angle Triangulars + Area of single Rectangle Total Area = 2(12) + 80 +16√13 = 104+16√13
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