need the lateral and total area of this figure

Question

anonymous · Answer

attachment

anonymous · Answer

anyone?

anonymous · Answer

Okay, so basically the first step of the problem is to find the area of one of the sides, right? And the sides are isosceles triangles with sides 12, 10, 10. Can you figure out the area of that triangle?

anonymous · Answer

I have the lateral as 180 but I need the total area

anonymous · Answer

180 lateral is not correct. For total you just add the area of the base, which is a 12-12-12 equilateral triangle.

anonymous · Answer

ok can you show me how to work this please

anonymous · Answer

Basically for both triangles, the 10-10-12 and the 12-12-12, you need to find the height. So, draw the triangle, then draw the height, which will divide it into two triangles with right angles, then use the pythagorean theorem to solve for the height, then use the height to solve for the area.

anonymous · Answer

so is the height 5?

anonymous · Answer

No, how did you get 5?

anonymous · Answer

not sure

anonymous · Answer

my brain is fried I have been stuck for over an hour

anonymous · Answer

|dw:1337294265323:dw| $$x^2+6^2=10^2$$