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What is the sum of the arithmetic sequence 9, 14, 19, …, if there are 36 terms?
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1º you have to find 36º term. \[a _{n}=a _{1}+(n-1)d\] use this formula, where d is the commun diference 2º find the sum using this formula: \[Sum = (a _{1}+a _{36})/2\]
i got 875 and then doing the second part i guess i screwed up an got 14144 o.o and that's not a choice
First term is 9. Common difference is 5 The sum of the sequence is given by: 9x + 5x(x - 1)/2 x is the number of terms When x = 38 the expression gives the value of 3,857
1º step:\[a _{36}=9+35*5=184\]
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