Find a basis for the space V of all skew-symmetric 3x3 matrices. What is the dimension of V?
I'll be back in a sec. Brewing some coffee. Would you like some?
Yeah, I will in maybe two hours =P
Well you need to remember that a basis for any vectorial space generates it and it's vectors are linear independent.
And 3x3 skew-symmetric matrix is something like this:
\[A=-A^T\]
:-)
Hmm thinking...
Do you have any idea to begin with?
Mm you need three matrices am I right?
Well the dimension is 3 haha
I am stupid haha
and I need a longer explanation b/c A=-A^T isn't gonna cut it
soy estupido haha
uff I almost burn my brain hehe
I told you linear algebra's no good!
Well I think that the three vectors are \[\left[\begin{matrix}0 & 1 & 0\\ -1 & 0 & 0\\ 0 & 0 & 0\end{matrix}\right]\]
Hmmm you're right
Is the idea of a basis clear to you?
Like you know why (1,0,0), (0,1,0),(0,0,1) is the basis of R^3?
yes.
Well then you know that the basic idea behind a basis is that you can get any vector of the space by forming a linear combination.
like \[\vec{v}=a\hat{i} + b\hat{j} + c\hat{k}\]
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