Question

Use the Binomial Theorem to find the coefficient of the x^8 y^3 term in the expansion of (2x^2+3y^3)^5
plzzzz show work thank you.

Answer 1

n C r = (n!)/(r!(n-r)!)


5 C 1 = (5!)/(1!*(5-1)!)


5 C 1 = (5!)/(1!*4!)


5 C 1 = (5*4!)/(1!*4!)


5 C 1 = (5)/(1!)


5 C 1 = (5)/(1)


5 C 1 = (5)/(1)


5 C 1 = 5

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(5 C 1)*(2^4)*(3^1)


(5)*(2^4)*(3^1)


(5)*(16)*(3)


240


So the coefficient of the x^8y^3 term is 240

Answer 2

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