Mathematics
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OpenStudy (anonymous):
Find the matrix of the linear transformation T(f(t)) = f(2t+1) from P2 to P2 with respect to the basis B (script B) = (f1 = 1 +2t^2, f2=1, f3=t)
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OpenStudy (anonymous):
halp!
OpenStudy (anonymous):
@No-data
OpenStudy (anonymous):
no-dataaaa!
OpenStudy (anonymous):
It really doesn't
OpenStudy (anonymous):
??
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OpenStudy (anonymous):
Fallingangel, don't ever take linear algebra. It is the worstest!
OpenStudy (anonymous):
@no-data see the pdf file.
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
I think you need to apply the transformation to each vector of the basis.
OpenStudy (anonymous):
and you form a matrix with the coefficients of the result in columns.
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OpenStudy (anonymous):
So would the first vector in the basis for f1 be [1,0,2] because of the standard basis [1,x,x^2]?
OpenStudy (anonymous):
I thought that is the way, but I'm checking. if its true.
OpenStudy (anonymous):
Hmm what is the result of apply the transformation to the f_1 vector?
OpenStudy (anonymous):
I got 3 + 8t + 8 t^2
OpenStudy (alexwee123):
ugh linear algebra o.0
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OpenStudy (anonymous):
haha true alex. It's sht sh(((ts
OpenStudy (anonymous):
*the
OpenStudy (anonymous):
\[T(f_1(t)) = f_1(2t+1)=1+2(2t+1)^2\]
OpenStudy (anonymous):
I got \(3 + 8t + 8t^2\) am I right?
OpenStudy (anonymous):
sec... I think there's something more you have to do. Let me pull up some pages from a book.
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OpenStudy (anonymous):
Ok
OpenStudy (anonymous):
So it looks like you first have to plug 2t+1 into the x's in your standard P2 polynomial first.
OpenStudy (anonymous):
So you'll have 4t^2+4t+1
OpenStudy (anonymous):
what is your standard polynomial?
OpenStudy (anonymous):
I guess I meant plug in 1 +2t^2 into our polynomial.
4(1+2t^2)^2 +4t +1 = 4(1+2t^2)(1+2t^2) +4t +1
=4(1 + 4t^2 +4t^4) +4t +1
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OpenStudy (anonymous):
P2: ax^2 +bx +c
OpenStudy (anonymous):
See I'm really confused. I think I'm going to stop right there b/c I'm not on the right track I don't think.
OpenStudy (anonymous):
You need to remember how to obtain the matrix of a transformation first.
OpenStudy (anonymous):
Always go back to your definitions and well understood theorems brinethery.
OpenStudy (anonymous):
Right now I don't remember well, and I don't have math books at work to help you as I wish. But I think that is the way.
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OpenStudy (anonymous):
take some rest if you need it.
OpenStudy (anonymous):
are you allright?
OpenStudy (anonymous):
I'm fine, I just really need help to this question
OpenStudy (anonymous):
Ok.
OpenStudy (anonymous):
How are you?
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OpenStudy (anonymous):
As I said you before, you just need to apply the transformation to each of the vectors of your basis. and form a matrix.
OpenStudy (anonymous):
with the results aligned in columns.
OpenStudy (anonymous):
I mean: \[\left[\begin{matrix} F^T(f_1(t))& F^T(f_2(t)) & F^T(f_3(t)) &\end{matrix}\right]\]
OpenStudy (anonymous):
Sorry I can't see you tube videos at work. =(
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OpenStudy (anonymous):
it's blocked.
OpenStudy (anonymous):
That's okay
OpenStudy (anonymous):
but what does it show the video?
OpenStudy (anonymous):
Argentine tango
OpenStudy (anonymous):
My goal in life is to travel to Buenos Aires and learn tango there
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OpenStudy (anonymous):
You mean one of the many goals on your life =P
OpenStudy (anonymous):
I have no other goals. If I could just dance then I would be happy lol
OpenStudy (anonymous):
look for punk tango on you tube.
OpenStudy (anonymous):
that is the tango i want to dance haha
OpenStudy (anonymous):
well thank you brinethery.
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OpenStudy (anonymous):
I really miss math.. snif snif haha
OpenStudy (anonymous):
see you!
OpenStudy (anonymous):
bye