Calculate the radius of convergence and the interval of convergence (with examination of the endpoints) for the following power series: \(\sum_{n=0}^{\infty} \frac{x^{2n}]{2n+1}\)
\[\sum_{n=0}^{\infty} \frac{x^{2n}}{2n+1}\]
ratio test should do it for this one
\[\lim_{n\to \infty}\frac{2n+3}{2n+1}=1\] pretty much by your eyeballs so \[|x^2|<1\] and now check at \(x=-1\) and \(x=1\)
thank you satellite
yw we still need to check the endpoints
actually there is very little to check, because at both \(x=1\) and \(x=-1\) you get \[\sum\frac{1}{2n+1}\] which certainly does not converge
yes i looked again it looks good but difficult to figure out how we came to result
we can do it more precisely if you like
yes i would be thankfull for it
|dw:1337304263450:dw|
Join our real-time social learning platform and learn together with your friends!