What is the solution of log 3x - 2125 = 3 ?
Choose one answer.
a. x = 1 over 3
b. x = 1
c. x = 7 over 3
d. x = 4
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OpenStudy (mertsj):
Add 2125 to both sides and then put the equation into its exponential form and solve for x.
OpenStudy (anonymous):
Crap sorry its supposed to be 3x-2 then 125=3
OpenStudy (mertsj):
\[\log_{3x-2} 125=3\]
OpenStudy (mertsj):
Is that it?
OpenStudy (anonymous):
yes!
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OpenStudy (mertsj):
\[(3x-2)^3=125\]
OpenStudy (mertsj):
\[(3x-2)^3=5^3\]
OpenStudy (mertsj):
Can you get it from there?
OpenStudy (anonymous):
what do I do know
OpenStudy (mertsj):
\[2^5=x^5\]
What would x be?
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OpenStudy (anonymous):
2?
OpenStudy (mertsj):
\[2^5=(2x)^5\]
OpenStudy (mertsj):
What would 2x be?
OpenStudy (anonymous):
4
OpenStudy (anonymous):
I have no clue..
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OpenStudy (mertsj):
Here is the concept I am trying to get across to you: If you have two expressions that are equal and the exponents are the same, the only way they could be equal is if the bases are also the same.
OpenStudy (mertsj):
\[2^3=5^3\]
Could that possible be true?
OpenStudy (anonymous):
no
OpenStudy (mertsj):
NO!!
OpenStudy (anonymous):
so would it be c
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