Suppose that the x-intercepts of a graph of y = f(x) are -9, and -5 What are the intercepts of a graph of y = 5f(x) ?
ugh algebra :/
Let's make up a function that has those x intercepts and find out.
y=f(x)=(x+9)(x+5)
Would you agree that the x intercepts of that function are -9 and -5?
yes
would i just apply = 5(x+9) 5(x+5)
Ok. Let's multiply it by 5 and see what happens: 5y=5f(x)=5(x+9)(x+5)
What are the x intercepts of the new function?
5x + 45 ? 5x + 25?
Have you heard of the concept that "if the product of factors is 0 then one of the factors must be 0"?
i haven't, but it makes sense
Then why did you say that the x intercepts of y = (x+9)(x+5) are -9 and -5 if you don't know that concept?
i am just very confused.. hah . sorry
x intercepts are found by letting y be 0 and solving for x.
i can do it if the number is after the equation or inside, i just dont understand what it means when the number comes before the f(x)
That means multiply the function by 5
what will happen to the graph in that case then. does it expand?
Here is what you need to learn: (x+9)(x+5)= 0 means that x +9=0 or x+5=0
If you multiply that function by 5 you have: 5(x+9)(x+5)=0 and that means that 5 = 0 or x+9=0 or x+5=0
Obviously 5 cannot equal 0 so it must be true the x+9=0 or x+5=0. In other words, the x intercepts do not change. It just means that the function undergoes a stretch factor of 5
ok so the intercepts for this one would be -9 and -5
yep
im going to go draw the graph to get a visual of the stretch factor, other than that i think i understand
thank you
yw. Just use your graphing calculator and you will see that they are both parabolas but that the second one is really skinny.
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