Write the following power series as a function e) \(\sum_{n=0}^{\infty}\frac{2^{n}x^{3n}}{n!}\)
Just for easier reading: \[\Large \sum_{n=0}^{\infty}\frac{2^{n}x^{3n}}{n!}\]
ok..
This isn't actually my best area of expertise unfortunately. Perhaps @joemath314159 help out with this?
ok any help would be apreciated
isnt it:\[\frac{2^nx^{3n}}{n!}=\frac{(2x^3)^n}{n!}\]So that summation is really just\[e^{2x^3}\]?
mm, that i really dont know..maybe George can answer..
I think that's right.
Im using the fact that:\[e^x=\sum_{n=0}^\infty \frac{x^n}{n!}\]in place of x we have 2x^3 though.
ok is this end solution, or is there someting needed to be add?
That should be it. they wanted you to write that power series as a function, and it turned out to be e^(2x^3). Done and done :)
ok thank you very much both of you :) i am happy that i found this website and you guys
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