Question

differentiate y=sqrt(3x^2-cos^2 4x

Answer 1

write it out as y= (3x^2 - cos^2 4x)^(1/2)
so you can use the power rule/chain rule...

Answer 2

\[\large y=(3x^2-\cos^24x)^{\frac {1}{2}}\]
\[\large y^'=\frac {1}{2}(3x^2-\cos^24x)^{-\frac {1}{2}}[3x^2-\cos^24x]^'\]

Answer 3

my latex is too slow to take the derivative of that part in the brackets... :(
but can you do it from here?

Answer 4

no i cannt

Answer 5

ok.. we'll just work with the derivative of what's in the brackets then.. ok?

Answer 6

okk

Answer 7

[ 3x^2−cos^2 4x ]′
can you do anything with this derivative?