How do I symbolize 3*(x+2)^2 + 5 to show 3x^2 + 12x + 27
\(\Large \color{MidnightBlue}{\Rightarrow (a + b)^2 = a^2 + 2ab + b^2 }\) Hint..
Also, remember PEMDAS.
3(2x^2 + 4x + 4 + 5)...?
\(\Large \color{MidnightBlue}{\Rightarrow 3(x + 2)(x + 2) + 5 }\)
I want to know how to symbolize it correcly.
What do you mean by symbolise?
ParthKohli the 3 in the equation you put only multiplies the (x+2)^2
\(\Large \color{MidnightBlue}{ \brack3[(x + 2)(x + 2)] + 3}\)
I did completing the square but I want to know how I should symbolize the factorization process.
I will post my thoughts okay then you can tell me if I did it right
\(\Large \color{MidnightBlue}{\Rightarrow 3(x^2 + 4x + 4) + 3 }\)
\(\Large \color{MidnightBlue}{\Rightarrow 3x^2 + 12x + 12 + 5 }\) \(\Large \color{MidnightBlue}{\Rightarrow 3x^2 + 12x + 17 }\)
The question is, complete the square of \[3x ^{2} + 12x + 9\]
Okay, that's easy.
Go ahead, I'll correct if any mistake
I know but I want to know how to symbolize it in vertex mode
My book says do this this 3(x^2 + 4x + 9) ) 3(x^2 + 4x + )+ 9) 3(x^2 + 4x + 4)+9 - 4) 3(x+3)^2 + 5
My book says to put the 9 outside of a bracket that you make @ParthKohli
But I think it's better to keep inside so it's mathematically correct
3x^2 + 12x + 27 /3 /3 /3 3(x^2 + 4x + 9), 3(x^2 + 4x +4 +9 - 4) (x^2 + 4x + 4) = (x+2)^2 3((x + 2)^2 +5)
Holy crap I figured it out myself!!!!!!!!!!!!!
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