Are the complex fractions the quantity (x^2 - x - 20 / 4) / ( x - 5 / 10) and the quantity (x^2 - x - 20 / x - 5) / (4/10) equivalent? Simplify each, and then explain why or why not.

Question

anonymous · Answer

yes both are equivalent  $$(a/b)\div(c/d)=(a/b)\times(d/c)$$

anonymous · Answer

exactly as @syam_krisna , says...

anonymous · Answer

why r dey equivalent?

anonymous · Answer

try simplify both fractions without multiplying... just leave it in factored form..

anonymous · Answer

ok.. 
let 
a = x^2 - x -20
b = 4
c = x-5
d = 10

anonymous · Answer

that first quantity is (a/b)/(c/d) correct?

anonymous · Answer

k

anonymous · Answer

let's simplify this..
$$\large \frac{a}{b}\div \frac{c}{d}=\frac{a}{b}\times \frac{d}{c}=\frac {ad}{bc}$$

anonymous · Answer

kkkkkk i got itttt hahahaha

anonymous · Answer

now do that with theother...

anonymous · Answer

at least i got practice my LaTex ing...

anonymous · Answer

the first one gives me x+4/40 right

anonymous · Answer

no...

anonymous · Answer

u sure???????? wat u got?

anonymous · Answer

5(x+4)/2

anonymous · Answer

want me to show?

anonymous · Answer

u sure? the equation is (x^2 - x - 20) / (4) / ( x - 5) / (10) try it again the problem is  wrote the equation wrong

anonymous · Answer

|dw:1337323832391:dw|