Question

The product of two consecutive positive integers are 1 more than their sum find the integers.

Answer 1

Or, use trial and error method.

Answer 2

It works with 2 and 3.

Answer 3

consecutive is the missing part

Answer 4

since they're consecutive, the equation is
x(x+1) = x + (x+1) + 1

Answer 5

\[x(x+1)=x+x+1+1\]

Answer 6

@satellite73 Oops :P

Answer 7

So this doesn't need a system.

Answer 8

\(\Large \color{MidnightBlue}{\Rightarrow x(x + 1) = 1 + x + x + 1 }\)

Answer 9

is the answer -1,2

Answer 10

but you are right you can probably do it by trial and error, although this is a quadratic so there should be two solutions
\[x^2+x=2x+2\]
\[x^2-x-2=0\]
\[(x-2)(x+1)=0\]
\[x=-1, x=2\] and so the two solutions are 2 and 3 or -1 and 0

Answer 11

@satellite73 You missed the POSITIVE part. Oops,

Answer 12

aaah so i did
it does say positive, doesn't it
solution is 2 and 3 as you said right at the start