Question

Find solution of quadratic equation: 4x^2+16=52

Answer 1

\(\Large \color{MidnightBlue}{\Rightarrow 4x^2 = 36 }\)
\(\Large \color{MidnightBlue}{\Rightarrow 4x^2 - 36 = 0 }\)
\(\Large \color{MidnightBlue}{\Rightarrow 4(x^2 - 9)=0 }\)
\(\Large \color{MidnightBlue}{\Rightarrow x^2 - 9 = 0 }\)
\(\Large \color{MidnightBlue}{\Rightarrow x^2 = 9 }\)
\(\Large \color{MidnightBlue}{\Rightarrow x = 3 }\)

Answer 2

@parthkohli \[x=\pm 3 \]

Answer 3

Oh yes..

Answer 4

OR \[\large 4x^2 = 36\] \[\large \frac{4x^2}{4} = \frac{36}{4}\] \[\large x^2 = 9\] \[\large \sqrt{x^2} = \sqrt{9}\] \[\large x = \pm 3\] whichever you find easier

Answer 5

or \[4x^2-36=0\]\[4(x^2-9)=0\]\[4(x-3)(x+3)=0\]\[x=3,-3\]

Answer 6

Thanks everyone :)

Answer 7

:D

Answer 8

OR
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nahh i got nothing

Answer 9

lol ewgee