calculate the degree of hardness of a water sample containing 0.001 mole of Mgso4 dissolved in 2 Litres of water?
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OpenStudy (anonymous):
@ujjwal
OpenStudy (anonymous):
mcq?
OpenStudy (anonymous):
no but i know the answer but cant solve for it..
OpenStudy (anonymous):
whats the formula for the harndess?
OpenStudy (anonymous):
ppm= x+50/e2
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OpenStudy (anonymous):
i am not sure bro, sorry...maybe others would help
OpenStudy (apoorvk):
degree of hardness is the no. of moles of the 'foreign' molecule divided by the no. of molecules of water.
OpenStudy (anonymous):
can anyone solve for it..............
OpenStudy (anonymous):
@apoorvk can u tell me step by step
OpenStudy (apoorvk):
you have two litres of water - that is 2 kilos - which is 2000gms.
one mole of water is 18gms. find out the no. of moles of water present.
you already have the no. of moles of MgSO4 present. - divide the two now
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OpenStudy (anonymous):
@apoorvk then the mole which i got is a huge number