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Chemistry 18 Online
OpenStudy (anonymous):

calculate the degree of hardness of a water sample containing 0.001 mole of Mgso4 dissolved in 2 Litres of water?

OpenStudy (anonymous):

@ujjwal

OpenStudy (anonymous):

mcq?

OpenStudy (anonymous):

no but i know the answer but cant solve for it..

OpenStudy (anonymous):

whats the formula for the harndess?

OpenStudy (anonymous):

ppm= x+50/e2

OpenStudy (anonymous):

i am not sure bro, sorry...maybe others would help

OpenStudy (apoorvk):

degree of hardness is the no. of moles of the 'foreign' molecule divided by the no. of molecules of water.

OpenStudy (anonymous):

can anyone solve for it..............

OpenStudy (anonymous):

@apoorvk can u tell me step by step

OpenStudy (apoorvk):

you have two litres of water - that is 2 kilos - which is 2000gms. one mole of water is 18gms. find out the no. of moles of water present. you already have the no. of moles of MgSO4 present. - divide the two now

OpenStudy (anonymous):

@apoorvk then the mole which i got is a huge number

OpenStudy (apoorvk):

how many moles of water did you get?

OpenStudy (anonymous):

111

OpenStudy (apoorvk):

that is right.

OpenStudy (anonymous):

then wat next

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