Question

64^(3 – x) = 4^2x solve and explain how

Answer 1

hint: \(\large 64 = 4^3\)

Answer 2

idk

Answer 3

replace 64 with 4^3 in your equation what will you have?

Answer 4

4^3-x=4^2x???

Answer 5

\[\LARGE (4^3)^{(3-x)} = 4^{2x}\]

got it?

Answer 6

ok yeah

Answer 7

okay...then remember that \[\LARGE (a^b)^c = a^{bc}?\]

Answer 8

Now, make up an equation of the exponents as the bases are same.

Answer 9

4^(9-3x)=4^2x?

Answer 10

Yes.


\(\Large \color{MidnightBlue}{\Rightarrow 9 - 3x = 2x }\)

Answer 11

yea

Answer 12

right! another property.. \[\LARGE a^x = a^y \rightarrow x = y\] that meant that if two similar bases with different exponents are equal then their exponents are equal...capsiche?

Answer 13

yea

Answer 14

^ I like this lgba :P

Answer 15

9=5x

Answer 16

x=9/5?

Answer 17

Divide both sides by 5 now.

Answer 18

Yes.

Answer 19

\[\Huge \color{red}{\checkmark}\]

Answer 20

lol im a fail

Answer 21

y?

Answer 22

i wrote the latex for that check wrong the first time haha