Question

Eliminate the parameter and write the correspnding rectangular equation whose graph represents the curve.
x=sqrt(t)
y=1-t

Answer 1

I got the x, t=x^2, but the y..

Answer 2

substitute that into the second equation...
y=1-x^2

Answer 3

Oh.. really? lmfao

Answer 4

I swear I look at things and put WAY too much thought into them.

Answer 5

@dpaInc how about for x=4+2cos(theta) and y=-1+2sin(theta)?

Answer 6

these are polar equations... change back using
x^2+y^2=r^2
tan(theta)=y/x
x=rcostheta
y=rsintheta

Answer 7

x=4+2cos(theta)-->(x-4/2)^2=cos^2theta

Answer 8

((x-4)/2)^2+((y-1)/2))^2=1