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Positive indices question :)
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\[(27x^3y ^{-6})^{1/3}\]
carry out (ab)^m = a^m*b^m
27^(1/3)*(x^3)^(1/3)*(y^(-6))^(1/3)
wow, i thought maybe first you change 27 to 3 to the power of 3? then use indice rules?
No?
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the one third becomes 3 route something
Whether you change the 27 to \(3^3\) before or after multiplying the exponents, either way you should get the same answer.
Do you know how to do the question nbouscal?
Yeah. dpaInc did the first step for you. Now you just multiply the exponents. Remember, \((x^a)^b=x^{ab}\)
Can you show me how the equation will look when I use the (ab)^m rule? It's tough to follow his..
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\(27^{1/3}\cdot (x^3)^{1/3}\cdot (y^{-6})^{1/3}\)
Ok, so I change 27 to 3^3 then use (xa)b ?
x(ab)
Yep.
Thanks xD
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