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Mathematics 12 Online
OpenStudy (anonymous):

Positive indices question :)

OpenStudy (anonymous):

\[(27x^3y ^{-6})^{1/3}\]

OpenStudy (anonymous):

carry out (ab)^m = a^m*b^m

OpenStudy (anonymous):

27^(1/3)*(x^3)^(1/3)*(y^(-6))^(1/3)

OpenStudy (anonymous):

wow, i thought maybe first you change 27 to 3 to the power of 3? then use indice rules?

OpenStudy (anonymous):

No?

OpenStudy (anonymous):

the one third becomes 3 route something

OpenStudy (anonymous):

Whether you change the 27 to \(3^3\) before or after multiplying the exponents, either way you should get the same answer.

OpenStudy (anonymous):

Do you know how to do the question nbouscal?

OpenStudy (anonymous):

Yeah. dpaInc did the first step for you. Now you just multiply the exponents. Remember, \((x^a)^b=x^{ab}\)

OpenStudy (anonymous):

Can you show me how the equation will look when I use the (ab)^m rule? It's tough to follow his..

OpenStudy (anonymous):

\(27^{1/3}\cdot (x^3)^{1/3}\cdot (y^{-6})^{1/3}\)

OpenStudy (anonymous):

Ok, so I change 27 to 3^3 then use (xa)b ?

OpenStudy (anonymous):

x(ab)

OpenStudy (anonymous):

Yep.

OpenStudy (anonymous):

Thanks xD

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