Question

A drawer contains 13 socks - 4 blue, 3 red, and 6 green. If four socks are drawn randomly (without replacement), the probability that three of them are green is approximately
Question 2 options:
a) 21.18%
b) 19.58%

Answer 1

I'll let Mr. Lgba answer on this one =)

Answer 2

lol no..i dont know probabilities

Answer 3

well i used to know them..not anymore

Answer 4

Okay, let me answer then :P

Answer 5

What is the probability of getting a green sock?

Answer 6

I guess it would be 6/13= 0.46%.

Answer 7

\( \frac{6}{13} \cdot \frac{5}{12} \cdot \frac{4}{11} \cdot \frac{7}{12}\) is the probability of choosing Green, Green, Green, not Green.

Answer 8

@ParthKohli

Answer 9

He's right lol

Answer 10

Where did 7/12 come from?

Answer 11

7/12 is the probability of NOT choosing a green one.

Answer 12

Since we have to choose it 3 times, not 4.

Answer 13

\[\frac{\left(\begin{matrix}6 \\ 3\end{matrix}\right)\left(\begin{matrix}7 \\ 1\end{matrix}\right)}{\left(\begin{matrix}13 \\ 4\end{matrix}\right)}\]
=0.1958

Answer 14

@ParthKohli I'm a bit confused on why the denominator is 12. (7/12)

Answer 15

The hypergeometric distribution applies to this problem. See above for solution.

Answer 16

Thank you @kropot72! :)

Answer 17

You're welcome :)