Question

1/(x-5)^4<0

Answer 1

This function is always greater than 0 unless x=5 in which case the fraction becomes 1/0 which is undefined. [This is because x-5 is raised to the power of 4 which is an even power and hence would always give you a positive answer]

Answer 2

how d i get the critical numbers since there is no variable on top

Answer 3

It's false!

Answer 4

would it just be 1, 5, and 0

Answer 5

critical number: x - 5 = 0

Answer 6

I have to find the critical numbers the graph it on a sign chart and answer in interval notation.

Answer 7

x - 5 = 0 --> x = ....

Answer 8

x=5 so that is a critical number but what about the 1 and zero, because 5 would be the exclusion right since its the denominator

Answer 9

Well 1-5=-4 but (-4)^4=(-4)*(-4)*(-4)*(-4)=256. 1/256 is +ve and exists. There not a critical point. Similarly with 0. You would get 0-5=-5 which will then be raised to 4 which would then give you another positive answer. And hence that's not a critical point either.

Answer 10

the problem was 1/(x-5)^4<0

Answer 11

i was wondering how you get the critical numbers since there is no variable on top is the 1 automatically a critical number then solve the denominator for the other and then 0