a student guesses the answer to 6 question on a true-false quiz find the probability that the indicated number of guesses are correct :exacly 4
Use the binomial probability distribution formula P(X = x) = (n C x)*(p)^(x)*(1-p)^(n-x) P(X = 4) = (6 C 4)*(0.5)^(4)*(1-0.5)^(6-4) P(X = 4) = (6 C 4)*(0.5)^(4)*(0.5)^(6-4) P(X = 4) = (15)*(0.5)^(4)*(0.5)^2 P(X = 4) = (15)*(0.0625)*(0.25) P(X = 4) = 0.234375 So the probability of getting exactly 4 questions correct is 0.234375
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give the value of the expression 11C4 a)330 b)220 c)110 d)550
give the value of the expression 11C4 a)330 b)220 c)110 d)550
n C r = (n!)/(r!(n-r)!) 11 C 4 = (11!)/(4!*(11-4)!) 11 C 4 = (11!)/(4!*7!) 11 C 4 = (11*10*9*8*7!)/(4!*7!) 11 C 4 = (11*10*9*8)/(4!) 11 C 4 = (11*10*9*8)/(4*3*2*1) 11 C 4 = (7920)/(24) 11 C 4 = 330
log of base 9 +log base of 2 a=log base 2 11
Can you draw this one out?
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