Which is the 25th term of the arithmetic sequence where a1 = 8 and a9 = 64?

Question

anonymous · Answer

$$a _{n}=a _{1}+(n-1)d$$
this is general formula for any arithmetic seequence term. So using it for the 9th term we can find commun diference d:
$$64=8+(9-1)d$$
d=56/8=7
now the 25th term is:
$$a _{25}=8+24*7=176$$

anonymous · Answer

What is the solution to the rational equation 4/3 plus the fraction 2 over x plus 5 = negative 6 over 3x plus 1

anonymous · Answer

not even thankyou for the previous one?

anonymous · Answer

it didn t send ? i apologize dearely my computer is stupid. thank you for your help i appreciate it

anonymous · Answer

(4/3)+2/(x+5)=-6/(3x+1)?

anonymous · Answer

yes

anonymous · Answer

left side:
$$4(x+5)+6\over 3(x+5)$$=
$$-6\over(3x+1)$$
now find comun denominator and add

anonymous · Answer

ok i got an answer. what did you get

anonymous · Answer

(4x+26)(3x+1)+(3x+15)6=0
12x$$12x ^{2}+4x+78x+26+18x+80=0$$
$$12x ^{2}+100x+106=0$$
solve this