Solve for x (3x)^6=3^-6
We can take the cube root of both sides to get (3x)^2 = 3^(-2) Now we can "take the square root", but must keep in mind that there is a positive and a negative answer, so that \[3x = \pm(3^{-1}) = \pm{1 \over 3}\]and hence \[x = \pm{1 \over 9}\]I'm assuming x is only allowed to be real. There are four additional complex solutions to this (which would come out at the point that I took the cube root), but I won't bother typing it out unless you want/need to know what they are.
the answer is 1/9 ?
Write both sides with the exponent of 6
positive or negative 1/9 Because a negative to an even power is positive.
\[(3x)^6=(\frac{1}{3})^6\]
no it (3^x)^6=3^-6
Since the expressions are equal and the exponents are the same, the bases must also be the same so write: \[3x=\frac{1}{3}\]
Solve that.
\[(3^x)^6=3^{6x}\]
So: \[3^{6x}=3^{-6}\]
So 6x=-6
x=-1
thank you !!!!!!!!!!!!!!!!!!!!
yw
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