Question

Andrew has made a set of cards where each card has one letter of the alphabet and no letters are repeated. If Andrew chooses 4 of these cards at random, how many combinations and permutations of these cards are there?14,950 c and 358,800 p

Answer 1

They are respectively \[{26! \over (4!)(22!)} = 14950\]and\[{26! \over 22!} = 358,800\]So those are correct.