Question

Convert ther rectangular coordinates (-2sqrt(3)),-2) in polar coordinates, in the interval (-pi,pi)

Answer 1

let's find magnitude and phase

Answer 2

I just need radius and theta

Answer 3

yes , radius is magnitude
theta is phase

Answer 4

I have those formulas but I never end up with the right answer

Answer 5

add the square of x and y and take square root of it

Answer 6

Radius is 4, but my theta is too large of a number

Answer 7

If it's too large maybe try subtracting 2pi? (that is just 1 revolution, so it's equivalent)

Answer 8

That is the part I think I am doing incorrectly, I can't figure out how to keep it in radians

Answer 9

So... is the angle you got 7pi/6?

Answer 10

If that's it, then your resulting angle should just be -5pi/6