Question

i need help with this problem... ill draw it..give me a minute please

Answer 1

\[(x ^{\frac{1}{3}}+8)(x ^{\frac{1}{3}}-1)=0\]

Answer 2

We essentially have a quadratic in x^(1/3); in other words, we basically have to solve
x^2 + 7x - 8 = 0
This can be done by factoring; we need to find two numbers that multiply to be -8 and add to be 7. 8 and -1 fit the bill, so our factorization is
(x^(1/3) + 8)(x^(1/3) - 1) = 0
Setting each factor equal to zero gives
x^(1/3) + 8 = 0
x^(1/3) = -8
x = -256
and
x^(1/3) - 1 = 0
x^(1/3) = 1
x = 1
So those are your two answers.

Answer 3

\[x ^{\frac{1}{3}}=-8, x=-512\]

Answer 4

\[x ^{\frac{1}{3}}=1, x=1\]

Answer 5

Ah why why am I bad at arithmetic yes that is right oh man i'm leaving now.

Answer 6

bye