Question

Solve the system by using elimination or elimination with multiplication. One point for the steps and one point for the correct solution.

3x + 4y = -2 and 2x - 3y = 10

Answer 1

1) Multiply equation 1 by 2.
2) Multiply equation 2 by 3.
3) Subtract both the equations.
4) Solve for y.
5) After solved, substitute the value of y in any of the equations and solve for x.

Answer 2

\(\Large \color{MidnightBlue}{\Rightarrow 6x + 8y = -4 \text{ and } 6x - 9y = 30 }\)

Subtract both

\(\Large \color{MidnightBlue}{\Rightarrow 17y = -34 }\)
\(\Large \color{MidnightBlue}{\Rightarrow y = -2 }\)

Substitute:

\(\Large \color{MidnightBlue}{\Rightarrow 6x - 16 = -4 }\)
\(\Large \color{MidnightBlue}{\Rightarrow 6x = 12 }\)
\(\Large \color{MidnightBlue}{\Rightarrow x = 6 }\)

Answer 3

3x+4y=-2
2x-3y=10

Multiply first equation by 3 and second equation by4
3(3x+4y)= 3*-2
4(2x-3y)=4*10

9x+12y=-6
8x-12y=40

Add equation 1 and 2

9x+8x+12y-12y=40-6

17x=34
x=34/17
x=2

Put x=2 in second equation 2x-3y=10
4-3y=10
-3y=10-4
-3y=6
y=6/-3
y=-2

therefore x=2 and y=-2

Answer 4

Oops, I meant x = 2

Answer 5

Thanks (: