Mathematics
22 Online
OpenStudy (sup_open~study):
i need some help
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OpenStudy (sup_open~study):
OpenStudy (aroub):
Maybe you can give it a try? Because it's similar to the one before
OpenStudy (sup_open~study):
ok can you check my answer ???
OpenStudy (anonymous):
its \[9\sqrt{2}\]
Using pythagoras formula
OpenStudy (aroub):
Sure =)
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OpenStudy (sup_open~study):
i have a new one i need help on but i will try to work it out first but here it is
OpenStudy (sup_open~study):
OpenStudy (aroub):
Yup! Work it out and we will check your answer :D
OpenStudy (sup_open~study):
is it a ??
OpenStudy (sup_open~study):
traile can you help me plz lol
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OpenStudy (sup_open~study):
@traile can you help me please
OpenStudy (anonymous):
C
OpenStudy (anonymous):
@Sup_open~study
do you want me to show the solution???
OpenStudy (sup_open~study):
ah i guessed that first then i guessed A lol yes plz
OpenStudy (anonymous):
|dw:1337432618145:dw
|\[6\sqrt{3}\]
and 6 are the legs
@Sup_open~study
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OpenStudy (anonymous):
just use sin60= x/12 you will get 6square root of 3
and cos60= x/12 you will get 6
OpenStudy (sup_open~study):
ah i messed up on that sin60 part thanks man
OpenStudy (anonymous):
xD, as long as you understand the concept man
OpenStudy (sup_open~study):
that's dude :)
OpenStudy (amorfide):
|dw:1337433703584:dw|
a²+b²=c²