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Mathematics 22 Online
OpenStudy (sup_open~study):

i need some help

OpenStudy (sup_open~study):

OpenStudy (aroub):

Maybe you can give it a try? Because it's similar to the one before

OpenStudy (sup_open~study):

ok can you check my answer ???

OpenStudy (anonymous):

its \[9\sqrt{2}\] Using pythagoras formula

OpenStudy (aroub):

Sure =)

OpenStudy (sup_open~study):

i have a new one i need help on but i will try to work it out first but here it is

OpenStudy (sup_open~study):

OpenStudy (aroub):

Yup! Work it out and we will check your answer :D

OpenStudy (sup_open~study):

is it a ??

OpenStudy (sup_open~study):

traile can you help me plz lol

OpenStudy (sup_open~study):

@traile can you help me please

OpenStudy (anonymous):

C

OpenStudy (anonymous):

@Sup_open~study do you want me to show the solution???

OpenStudy (sup_open~study):

ah i guessed that first then i guessed A lol yes plz

OpenStudy (anonymous):

|dw:1337432618145:dw |\[6\sqrt{3}\] and 6 are the legs @Sup_open~study

OpenStudy (anonymous):

just use sin60= x/12 you will get 6square root of 3 and cos60= x/12 you will get 6

OpenStudy (sup_open~study):

ah i messed up on that sin60 part thanks man

OpenStudy (anonymous):

xD, as long as you understand the concept man

OpenStudy (sup_open~study):

that's dude :)

OpenStudy (amorfide):

|dw:1337433703584:dw| a²+b²=c²

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